Proszę o rozwiązanie następujących działań
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Z góry dzięki za odpowiedzi. Pozdrawiam
(a+2)/(a^2 -4a+4) : (a^2 +2a)/(ab-2b) =
=(a+2)/(a-2)^2 : (a^2 +2a)/(ab-2b) =
=(a+2)/[(a-2)(a-2) * b(a-2)/a(a+2) =
= b/[a(a-b)] =
= b/(a^2 - 2a)
(2a^2 -10a)/b^2 : (a^2 -25)/b =
= 2a(a-5)/b^2 * b/[(a+5)(a-5) =
= 2a/[b(a+5)] =
= 2a/(ab+5b)
x/(a+x) * (a+x)/(a^2 + x^2) =
= x/(a^2 +x^2)
(x^2 -3x)/y * y^2/(2x-6) =
= x(x-3) * y/2(x-3) =
= xy/2
1/(2a+1) - 1/(1-2a) =
= [(1-2a)-(2a+1)]/[(1+2a)(1-2a)] =
= (1-2a-2a-1)/(1-4a^2)
= -4a/(1-4a^2)
(x+1)/(2x-x) + (x-2)(x+1) =
=(x+1)/x +(x-2)(x+1) =
= [(x+1)^2 + x(x-2)/[x(x+1)] =
=(x^2 +2x+1 +x^2 -2x)/[x(x+1)] =
=(2x^2 +1)/(x^2 + x)
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1.
(a+2)/(a^2 -4a+4) : (a^2 +2a)/(ab-2b) =
=(a+2)/(a-2)^2 : (a^2 +2a)/(ab-2b) =
=(a+2)/[(a-2)(a-2) * b(a-2)/a(a+2) =
= b/[a(a-b)] =
= b/(a^2 - 2a)
2.
(2a^2 -10a)/b^2 : (a^2 -25)/b =
= 2a(a-5)/b^2 * b/[(a+5)(a-5) =
= 2a/[b(a+5)] =
= 2a/(ab+5b)
3.
x/(a+x) * (a+x)/(a^2 + x^2) =
= x/(a^2 +x^2)
4.
(x^2 -3x)/y * y^2/(2x-6) =
= x(x-3) * y/2(x-3) =
= xy/2
5.
1/(2a+1) - 1/(1-2a) =
= [(1-2a)-(2a+1)]/[(1+2a)(1-2a)] =
= (1-2a-2a-1)/(1-4a^2)
= -4a/(1-4a^2)
6.
(x+1)/(2x-x) + (x-2)(x+1) =
=(x+1)/x +(x-2)(x+1) =
= [(x+1)^2 + x(x-2)/[x(x+1)] =
=(x^2 +2x+1 +x^2 -2x)/[x(x+1)] =
=(2x^2 +1)/(x^2 + x)