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[H⁺] = √ (2 x 10⁻⁵ x 0,2)
[H⁺] = √ (4 x 10⁻⁶)
[H⁺] = 2 x 10⁻³ Molar
pH = - log [H⁺]
pH = - log [2 x 10⁻³]
pH = 3 - log 2