Garam NH4Cl (Mr=53,5) sebanyak X gram dicampur dengan 500ml larutan NH4OH dicampur dengan 500 ml larutan NH4OH 0,1 M (Kb= 2 x 10^-5). Supaya diperoleh campuran dengan pH=9 maka berat X adalah...
A. 0,2675 gram
B. 0,535 gram
C. 1,07 gram
D. 2,675 gram
E. 5,35 gram
A. 0,2675 gram
B. 0,535 gram
C. 1,07 gram
D. 2,675 gram
E. 5,35 gram
fatihahalhusna
![\displaystyle mol\ NH_4Cl=\frac{x}{53,5}\ mol\\mol\ NH_4OH=\frac{500}{1000}\times0.1=0,05\ mol\\\\pH=9\rightarrow pOH=5\rightarrow [OH^-]=10^{-5}\ M\\\\{[OH^-]}=K_b\times\frac{mol\ NH_4OH}{mol\ NH_4Cl}\\\\10^{-5}=2\times{10^{-5}}\times\frac{0,05}{\frac{x}{53,5}}\\\\\frac{x}{53,5}=0,1\rightarrow \boxed{\boxed{\bold{5,35\ gram}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle+mol%5C+NH_4Cl%3D%5Cfrac%7Bx%7D%7B53%2C5%7D%5C+mol%5C%5Cmol%5C+NH_4OH%3D%5Cfrac%7B500%7D%7B1000%7D%5Ctimes0.1%3D0%2C05%5C+mol%5C%5C%5C%5CpH%3D9%5Crightarrow+pOH%3D5%5Crightarrow+%5BOH%5E-%5D%3D10%5E%7B-5%7D%5C+M%5C%5C%5C%5C%7B%5BOH%5E-%5D%7D%3DK_b%5Ctimes%5Cfrac%7Bmol%5C+NH_4OH%7D%7Bmol%5C+NH_4Cl%7D%5C%5C%5C%5C10%5E%7B-5%7D%3D2%5Ctimes%7B10%5E%7B-5%7D%7D%5Ctimes%5Cfrac%7B0%2C05%7D%7B%5Cfrac%7Bx%7D%7B53%2C5%7D%7D%5C%5C%5C%5C%5Cfrac%7Bx%7D%7B53%2C5%7D%3D0%2C1%5Crightarrow+%5Cboxed%7B%5Cboxed%7B%5Cbold%7B5%2C35%5C+gram%7D%7D%7D "\displaystyle mol\ NH_4Cl=\frac{x}{53,5}\ mol\\mol\ NH_4OH=\frac{500}{1000}\times0.1=0,05\ mol\\\\pH=9\rightarrow pOH=5\rightarrow [OH^-]=10^{-5}\ M\\\\{[OH^-]}=K_b\times\frac{mol\ NH_4OH}{mol\ NH_4Cl}\\\\10^{-5}=2\times{10^{-5}}\times\frac{0,05}{\frac{x}{53,5}}\\\\\frac{x}{53,5}=0,1\rightarrow \boxed{\boxed{\bold{5,35\ gram}}}")
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