irenefajrin
1) 2× pi × jari jari × banyak putaran roda = 2×22/7×56×200= 44×8×200=70.400 cm = 0, 704 km
irenefajrin
2) kerangka balok = luas permukaan balok. Lp balok = 2( pl+lt+pt) = 2{(12×8)+(8×6)×(12×6)} = 2(96+48+72) = 2× 216 =432 cm. 6,5 m = 650 cm. jadi , 650 - 432 = 218 cm = 2,18 m
gifitafa
1. Panjang lintasan = KO*200 = pi*d*200 = 22/7*112*200 = 22*16*200 = 70.400 cm note = * (kali)
2) 218 cm = 2, 18 m
= pi*d*200
= 22/7*112*200
= 22*16*200
= 70.400 cm
note = * (kali)