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pOH = 14 - pH
pOH = 14 - 9
pOH = 5
[OH⁻] = 10⁻⁵
√ (Ka Ma) = 10⁻⁵
Ka (0,01) = 10⁻¹⁰
Ka = 10⁻⁸
α = √ (Ka / Ma)
α = √ (10⁻⁸ / 0,01)
α = √ 10⁻⁶
α = 10⁻³
α = 0,001