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f'x= 6x² -12x =0 ... x=0 dan x=2
f" x = 12x -12
untuk x=0 ... f"x= -12 <0 ... nilai maksimum f(0)= 2 .0 - 6. 0 +3=3
untuk x=2 ... f"x= 24-12=12 >0 ... nilai minimm f(2)= 2 .2³ - 6. 2² +3= - 5