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F(x) =y=x²-3x+1
Y=(2)²-3(2)+1
Y=-1
M=f'(x)=2x-3
M=2(2)-3
M=1
Pgs = y-y1=m(x-x1)
Y+1=1(x-2)
X-y=3 atau x-y-3=0