Oblicz:
Dochodzę do postaci:
I pytanie teraz, jak dalej to rozpisać?
2cos⁴α/ sin²α·sin²α /cos²α(sin²α-1)=
=2cos⁴α/cos²α(sin²α-1)=
=2cos²α/sin²α-1=
=2cos²α/-cos²α=
=-2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
2cos⁴α/ sin²α·sin²α /cos²α(sin²α-1)=
=2cos⁴α/cos²α(sin²α-1)=
=2cos²α/sin²α-1=
=2cos²α/-cos²α=
=-2