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ż=x - yj
ż=z
(ż)²-2z=3
ż²-2z=3
-z²=3 /*-
z²=3
z=∫3
(x-yj)²-2(x+yj)=3
x²-2xyj+y²j²-2x-2yj=3
x²+y²j²=3
z=x+yj
3=x²+y²j²
x²+y²j²=3
x+yj=√3
z=√3
Odp. Z=√3