oblicz x1 i x2 w funkcji y=2xdo kwadratu -8
y=2x²-8
Δ=b²-4ac=0+64=64
√Δ=8
x₁=[-b-√Δ]/2a=-8/4=-2
x₂=[-b+√Δ]/2a=8/4=2
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y=2x²-8
Δ=b²-4ac=0+64=64
√Δ=8
x₁=[-b-√Δ]/2a=-8/4=-2
x₂=[-b+√Δ]/2a=8/4=2
y=2x²-8
Δ=b²-4ac=0+64=64
√Δ=8
x₁=[-b-√Δ]/2a=-8/4=-2
x₂=[-b+√Δ]/2a=8/4=2