oblicz (2a-1) do potęgi 3
(2a-1)³=(2a)³-1³=8a³-1
(2a-1)³
2a·2a·2a=8a³
1·1·1=1
Czyli:
(2a-1)³=8a³-1
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(2a-1)³=(2a)³-1³=8a³-1
(2a-1)³
2a·2a·2a=8a³
1·1·1=1
Czyli:
(2a-1)³=8a³-1