oblicz V i Pc graniastosłupa prawidłowego czworokątnego o boku 10 cm i wysokości 10cm
a = 10 cm
h = 10 cm
Jest to sześcian.
V = a^3 = 10^3 = 1000
P = 6 a^2 = 6*10^2 = 600
Odp. V = 1000 cm^3, P = 600 cm^2
==============================
a=10cm
h=10cm
Pp-pole podstawy
V=Pp*h
Pp=10x10
Pp=100cm
V=100x10
V=1000cm3
Pc=2Pp+Pb
Pb=(10x10)x6
Pb=600cm2
Pc=2x100+600
Pc=800cm2
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a = 10 cm
h = 10 cm
Jest to sześcian.
V = a^3 = 10^3 = 1000
P = 6 a^2 = 6*10^2 = 600
Odp. V = 1000 cm^3, P = 600 cm^2
==============================
a=10cm
h=10cm
Pp-pole podstawy
V=Pp*h
Pp=10x10
Pp=100cm
V=100x10
V=1000cm3
Pc=2Pp+Pb
Pp=100cm
Pb=(10x10)x6
Pb=600cm2
Pc=2x100+600
Pc=800cm2