Oblicz skład procentowy(% masowy) pierwiastków chemicznych w metanie.
mCH4=12u+4*1u=16u
%C = 12*100%/16 = 75% C
%H = 4*100%/16 = 25% H
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
mCH4=12u+4*1u=16u
%C = 12*100%/16 = 75% C
%H = 4*100%/16 = 25% H