Oblicz pole trójkąta równobocznego, jeśli pole koła wpisanego w ten trójkąt wynosi 36 pi
r = 1//3h
h = a√3/2 zatem r = a√3/6
Pkoła = πr²
36π = π (a√3/6)²
36π = π(a²*3/36)
36² = 3a²
36²/3 = a²
a = 6/√3 = 6√3/3 = 2√3
P = a²√3/4
P = (2√3)²√3/4 = 4*3√3/4 = 3√3
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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r = 1//3h
h = a√3/2 zatem r = a√3/6
Pkoła = πr²
36π = π (a√3/6)²
36π = π(a²*3/36)
36² = 3a²
36²/3 = a²
a = 6/√3 = 6√3/3 = 2√3
P = a²√3/4
P = (2√3)²√3/4 = 4*3√3/4 = 3√3
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)