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BC=[9,-12]
P=|det(BA,BC)|=|15*12+4*9|=216
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rownanie BC: y=-3/4(x+1)-5
rownanie okregu o srodku A
(x-2)²+(y+1)=100*3
Rozwiazanie ukladu daje punty B i D
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PS: √10=3²+1² odladasz 5 trojkatow od C i od A aby narysowac okregi