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d=4√2
średnica = d
r=½d
r=2√2
P=π(2√2)²
P=8π
Ob=2πr
Ob=4√2π
z twierdzenia Pitagorasa:
4²+4²=d²
16+16=d²
d=√32=5,66-średnica koła
r=2,83
Pk=πr²
Pk=3,14*5,66=17,77cm
Ok=2πr
Ok=2*3,14*2,83
Ok=17,77cm