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10:2=5
a²+b²=c²
12²+5²=c²
144+25=c²
c²=169
c=√169=13
Ob= 2+13+12+13=40
Odp. Obwód tego trapezu wynosi 40 cm.
12² + 5² = x²
144 + 25 = x²
169 = x²
13 = x
Obw. = 5 + 2 + 5 + 13 + 2 + 13 = 40 cm
załacznik