Oblicz obwód okręgu o równaniu x2 + y2 +4x – 6y – 4 = 0
(x+2)²-4+(y-3)²-9-4=0
(x+2)²+(y-3)²=17
r=√17
2πr=2π√17
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(x+2)²-4+(y-3)²-9-4=0
(x+2)²+(y-3)²=17
r=√17
2πr=2π√17