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C2H4+3O2---2CO2+2H20
MC2H4=12+12+4=28g/mol
MCO2=12+32=44g/mol
28g C2H4-88gCO2
xg C2H4-8,8g
x=2,8g
d=m/v
v=m/d=2,8/1,5=1,86dm3
nalezy uzyc 1,86dm3 etenu aby uzyskac 8,8 CO2