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Pp=a²=4²=16
c=dł. krawedzi bocznej=6cm
d=przekatna podstawy=a√2=4√2
1/2a=2√2
H=wysokosc bryły
z pitagorasa;
c²=H²+(1/2a)²
6²=H²+(2√2)²
H=√[36-8]=√28=2√7
v=1/3 PpH=1/3*16*2√7=32√7/3 cm³