Oblicz objętość i pole powierzchni całkowitej prostopadłościanu o kraędziach 3,6 i 7
a=3
b=6
c=7
v=a*b*c
v=3*6*7=126
Pc=2Pp+Pb
Pp=3*6=18
Pb=2*3*7+2*6*7=42+84=126
Pc=2*18+126=36+126=162
c=h=7
V=a*b*h
V=3*6*7
V=126 jednostek ³
P=2ab+2bh+2ah
P=2*3*6+2*6*7+2*3*7
P=36+84+42
P=162 jednostek ²
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a=3
b=6
c=7
v=a*b*c
v=3*6*7=126
Pc=2Pp+Pb
Pp=3*6=18
Pb=2*3*7+2*6*7=42+84=126
Pc=2*18+126=36+126=162
a=3
b=6
c=h=7
V=a*b*h
V=3*6*7
V=126 jednostek ³
P=2ab+2bh+2ah
P=2*3*6+2*6*7+2*3*7
P=36+84+42
P=162 jednostek ²