mCa=40u Ca + 2HNO3--->Ca(NO3)2 + H2 40g Ca---------22,4dm3 wodoru(z reakcji) 2g Ca----------xdm3 wodoru x=2*22,4/40x=1,12dm3 wodoru
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2g ca=x dm
40-22,4
x=1,12 dm3 h2
mCa=40u
Ca + 2HNO3--->Ca(NO3)2 + H2
40g Ca---------22,4dm3 wodoru(z reakcji)
2g Ca----------xdm3 wodoru
x=2*22,4/40
x=1,12dm3 wodoru