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(2n-2)(2n-1)n = 360
(4n² - 6n + 2)n = 360
4n³ - 6n² + 2n - 360 = 0
2n³ - 3n² + n - 180 = 0
W(5) = 0
(n-5)(2n²+7n+36) = 0
n-5 = 0 lub 2n² + 7n + 36 = 0
n = 5 brak rozwiązań; Δ<0
n = 5