Oblicz masę molową i skład procentowy glikolu etylenowego.
glikol etylowy: C₂H₄(OH)₂
M[C₂H₄(OH)₂]=2*12g/mol+6*1g/mol+2*16g/mol=24g/mol+6g/mol+32g/mol=62g/mol
%C=24g/62g * 100%
%C=38,7%
%H=6g/62g * 100%
%H=9,7%
%O=32g/62g * 100%
%O=51,6%
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glikol etylowy: C₂H₄(OH)₂
M[C₂H₄(OH)₂]=2*12g/mol+6*1g/mol+2*16g/mol=24g/mol+6g/mol+32g/mol=62g/mol
%C=24g/62g * 100%
%C=38,7%
%H=6g/62g * 100%
%H=9,7%
%O=32g/62g * 100%
%O=51,6%