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Masa cząsteczkowa kwasu siarkowego (VI) wynosi 98 unitów, bo
4*16u+32u+2*1u= 98u (mS=32u; mO=16u, mH=1u)
m= 2*1u+32u+3*16u=2u+32u+48u=82
H2SO4 kwas siarkowy VI
m=2*1u+32u+4*16=2u+32u+64u=98