Oblicz masę : a) 3 moli ołowiu b) 5 moli węglanu potasu c) 0,5 mola wapnia d)2 moli kwasu siarkowego(VI)
Pb
1m=207,2g
3m=x
x=621,6g
K2CO3
1m=138,205g (39,098*2+12,0107+15,99*3)
5m=x
x= 691,025g
Ca
1m=40,078g
0,5m=x
x=20,039
H2SO4
1m=98,08g (1*2+32+15,99*4)
2m=196,16
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Pb
1m=207,2g
3m=x
x=621,6g
K2CO3
1m=138,205g (39,098*2+12,0107+15,99*3)
5m=x
x= 691,025g
Ca
1m=40,078g
0,5m=x
x=20,039
H2SO4
1m=98,08g (1*2+32+15,99*4)
2m=196,16