Oblicz jaką objętość w warunkach normalnych zajmie 35g chloru
n=m/M
n=35/71
n=0,49 mola
1 mol-22,4
0,49 - x
x= 10,98
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n=m/M
n=35/71
n=0,49 mola
1 mol-22,4
0,49 - x
x= 10,98