December 2018 1 15 Report
Oblicz:
a) log o podstawie 125 z 25=
b) log o podstawie 7 pierwiastek 7 z 49=
c) 2 log o postawie pierwiastek 5 z 5 - log o podstawie pierwiastek 5 z 125 + log o postawie pierwiastek 5 z 5 pierwiastek 5=

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