oblicz 1) sin 120 stopni 2) cos 240 3) ctg 660 4) sin(-510 stopni) 5)cos(-510)
1) sin120° = sin(90°+30°) = cos30° = √3/2
2) cos240° = cos(180°+60°) = -cos60°=-½
3) ctg660°= cos(360°+300°) = cos300° = cos(270°+30°)= sin30°= ½
4) sin(-510°) = -sin510°= -sin(360°+150°) = -sin150°= -sin(90°+60°)= -cos60°= -½
5) cos(-510°) = cos510°= cos(360°+150°) = cos150°= cos(90°+60°) = -sin60°= -√3/2
rozwiazanie w załaczniku
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1) sin120° = sin(90°+30°) = cos30° = √3/2
2) cos240° = cos(180°+60°) = -cos60°=-½
3) ctg660°= cos(360°+300°) = cos300° = cos(270°+30°)= sin30°= ½
4) sin(-510°) = -sin510°= -sin(360°+150°) = -sin150°= -sin(90°+60°)= -cos60°= -½
5) cos(-510°) = cos510°= cos(360°+150°) = cos150°= cos(90°+60°) = -sin60°= -√3/2
rozwiazanie w załaczniku