Question

Nomor 20 bantuannya tolong..​

Answer 1

Kekekalan Momentum arah sb x.

m₁. v₁. sin 60 + m₂. v₂ = (m₁+m₂).v'.cos θ

m. 10. 0,5√3 + m. (-2) = 2.m.v'. cos θ

5√3 - 2 = 2.v'.cοs θ (1)

Kekekalan Momentum arah sb y.

m₁. v₁. cos 60 = (m₁+m₂).v'.sin θ

m. v₁. cos 60 = 2.m.v'.sin θ

v₁. cos 60 = 2.v'.sin θ

10. 0,5 = 2.v'.sin θ

5 = 2.v'.sin θ (2)

(2) dibagi (1)

tan θ = 5/(5√3-2)

tan θ = 0,75

θ = tan⁻¹ 0,75 = 36,87°