Nilai 
yang memenuhi ![4^{x+2}= \sqrt[3]{16^{x+5} }](https://tex.z-dn.net/?f=4%5E%7Bx%2B2%7D%3D+%5Csqrt%5B3%5D%7B16%5E%7Bx%2B5%7D+%7D+ "4^{x+2}= \sqrt[3]{16^{x+5} }")
adalah...
bennysiahaaan
![4^{x+2} = \sqrt[3]{16^{x+5}} \\ 4^{x+2} = 16^{\frac{x+5}{3}} \\ 4^{x+2} = 4^{\frac{2(x+5)}{3}} \\ \\ x+2 = \frac{2}{3}(x+5) \\ 3(x+2) = 2(x+5) \\ 3x + 6 = 2x + 10 \\ x = 4 \\ \\ 2^x = 2^4 = 16](https://tex.z-dn.net/?f=4%5E%7Bx%2B2%7D+%3D+%5Csqrt%5B3%5D%7B16%5E%7Bx%2B5%7D%7D+%5C%5C+4%5E%7Bx%2B2%7D+%3D+16%5E%7B%5Cfrac%7Bx%2B5%7D%7B3%7D%7D+%5C%5C+4%5E%7Bx%2B2%7D+%3D+4%5E%7B%5Cfrac%7B2%28x%2B5%29%7D%7B3%7D%7D+%5C%5C+%5C%5C+x%2B2+%3D+%5Cfrac%7B2%7D%7B3%7D%28x%2B5%29+%5C%5C+3%28x%2B2%29+%3D+2%28x%2B5%29+%5C%5C+3x+%2B+6+%3D+2x+%2B+10+%5C%5C+x+%3D+4+%5C%5C+%5C%5C+2%5Ex+%3D+2%5E4+%3D+16 "4^{x+2} = \sqrt[3]{16^{x+5}} \\ 4^{x+2} = 16^{\frac{x+5}{3}} \\ 4^{x+2} = 4^{\frac{2(x+5)}{3}} \\ \\ x+2 = \frac{2}{3}(x+5) \\ 3(x+2) = 2(x+5) \\ 3x + 6 = 2x + 10 \\ x = 4 \\ \\ 2^x = 2^4 = 16")
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