Nierównośc.
3x+6≤ 2π+πx
3x -πx = 2π -6
x(3 -π) = 2(π -3)
x(3 -π) = 2(-3+ π)
x (3 -π) = -2(3 -π) /:(3 -π)
x = -2
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Nierównośc.
3x+6≤ 2π+πx
3x -πx = 2π -6
x(3 -π) = 2(π -3)
x(3 -π) = 2(-3+ π)
x (3 -π) = -2(3 -π) /:(3 -π)
x = -2