prosze o rozwiązanie dwóch równan
1.
x+1/√2 ≤√2
2. 2x-8>√7x- 4√7
x+1/√2≤√2 /·√2
x+1≤√2·√2
x+1≤2
x≤2-1
x≤1
2.
2x-8>√7x-4√7
2x-√7x>8-4√7x /:√7
2x-x<8-4
x<4
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1.
x+1/√2≤√2 /·√2
x+1≤√2·√2
x+1≤2
x≤2-1
x≤1
2.
2x-8>√7x-4√7
2x-√7x>8-4√7x /:√7
2x-x<8-4
x<4