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h (x) = f (x+1) + g ( x^2 +3 )
Gdy
f(x)=x^2 +2x+3
g(x)=x-5
Rozwiązanie:
h(x) = [(x+1)²+2(x+1)+3]+[x²+3-5]
h(x) = x²+2x+1+2x+2+3+x²+3-5
h(x) = 2x²+4x+4
h(x) = 2(x²+2x+2)