Do 200g 20% roztworu azotanu (V) sodu dosypano 0,5 mola suchego azotanu (V) sodu. Ile wynosi stężenie procentowe?
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M NaNO3=85g/mol
n=0,5mola
m=n*M
m=0,5*85
m = 42,5g
mr=200g
Cp=20%
ms=Cp*mr/100%
ms=20*200/100
ms = 40g soli
Po dosypaniu 0,5mola, czyli 42,5g
ms=82,5g
mr=242,5g
Cp=ms*100%/mr
Cp=82,5*100/242,5
Cp = 34%