Oblicz entalpię reakcji : 3C2H2(g) -> C6H6(c) na podstawie ciepeł spalania acetylenu i benzenu:
delta H spal = -3279 kJ/mol dla benzenu
delta H spal = -1300 kJ/ mol dla acetylenu
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c2h2 + 5/2 o2 -> 2 o2 + h2o /*3 H1
C6h6 + 15/2 o2 -> 6 co2 + 3h2o H2
3H1 - H2= - 3900 kj/mol + 3279 kj/mol = -621 kj/mol