m air panas = 1 kg
m air dingin = 200 gr = 0,2 kg
Ta =..??
berarti
Q lepas = Q terima
m .air panas x c air panas x delta T = m air dingin x c air dingin x delta T
1 x (70-Ta) = 0,2 x (Ta -10)
70 - Ta = 0,2 Ta - 2
-Ta - 0,2Ta = -2 - 70
-1,2 Ta = -72
Ta = 72/1,2
Ta = 720/12
Ta = 60
suhu akhir campuran = 60°C
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m air panas = 1 kg
m air dingin = 200 gr = 0,2 kg
Ta =..??
berarti
Q lepas = Q terima
m .air panas x c air panas x delta T = m air dingin x c air dingin x delta T
1 x (70-Ta) = 0,2 x (Ta -10)
70 - Ta = 0,2 Ta - 2
-Ta - 0,2Ta = -2 - 70
-1,2 Ta = -72
Ta = 72/1,2
Ta = 720/12
Ta = 60
suhu akhir campuran = 60°C