Me pueden resolver estas dos ecuaciones por la formula general ocupo toda la ecuación completa X2-5x=0 X2=-1 Ayuda la ocupo para en menos de 10 minutos gracias
x = [-b±√(b²-4ac)]/2a x = [-(-5)±√((-5)²-4*1*0)]/2(1) x = [5±√(25-0)]/2 x = [5±√25]/2 x = [5±5]/2 x = (5+5)/2 x = (5-5)/2 x = 10/2 x = 0/2 x1 = 5 x2 = 0
ECUACION 2 x²=-1 x²+1=0
a=1 b=0 c=1
x = [-b±√(b²-4ac)]/2a x = [-0±√(0²-4(1)(1))]/2(1) x = [±√-4]/2 x = ±2i/2 x = ±1i x1= i x2= -i
x²-5x=0
a = 1 b = -5 c=0
x = [-b±√(b²-4ac)]/2a
x = [-(-5)±√((-5)²-4*1*0)]/2(1)
x = [5±√(25-0)]/2
x = [5±√25]/2
x = [5±5]/2
x = (5+5)/2 x = (5-5)/2
x = 10/2 x = 0/2
x1 = 5 x2 = 0
ECUACION 2
x²=-1
x²+1=0
a=1 b=0 c=1
x = [-b±√(b²-4ac)]/2a
x = [-0±√(0²-4(1)(1))]/2(1)
x = [±√-4]/2
x = ±2i/2
x = ±1i
x1= i x2= -i