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√(x + 10) < √(x + 2) + 2Kuadratkan kdua rua
x + 10 < x + 6 + 4√(x + 2)
4 < 4√(x + 2)
√(x + 2) > 1
x + 2 > 1
x > -1 ... (1)
√(x + 10) ≥ 0
x ≥ -10 ... (2)
√(x + 2) ≥ 0
x ≥ -2 ... (3)
Nilai x yg memenuhi :
Irisan (1) (2) dan (3)
x > -1
Opsi E