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Δx=4 cm=0,04 m
dit: a.k=..?
b.Ep=..?
a.k=F/Δx=10/0,04=250 N/m
b.Ep=1/2.k.x^2
=1/2.250.(0,04)^2
=125.0,0016
=0,2 J
2.Ep=1 j
k=100 N/m
F=..?
Ep=1/2.k.x^2
1=1/2.100.x^2
x^2=0,02 m
F=k.Δx
F=100.0,02=2 N
konstanta pegas:
energi potensial pegas:
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