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segitiga berbentu siku-siku karna sisi-sisinya ( 8,6,10)
luas = 1/2 x a x t
= 1/2 x 8 x 6
= 4 x 6
= 24 cm²
soal B
segitiga sembarang , dengan sisi ( 9,11,8)
s = 1/2 x ( 9 + 11 + 8)
= 1/2 x 28
= 14
soal C
segitiga sembarang
s = 1/2 x ( 12 +20 + 24)
= 1/2 x 56
= 28