Najgłebsze miejsca w oceanach to rowy. Oblicz ciśnienie panujące na dnie Rowu Mariańskiego. Przyjmij gęstość wody słonej (1030 kg/m3)
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h = 10 911 m (głębokość Rowu Mariańskiego)
g =![10 \frac{m}{s^{2}} 10 \frac{m}{s^{2}}](https://tex.z-dn.net/?f=10+%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
ρ (greckie ro)=![1030 \frac{kg}{m^{3}} 1030 \frac{kg}{m^{3}}](https://tex.z-dn.net/?f=1030+%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%7D)
p = ?
p =![1030 \frac{kg}{m^{3}} \cdot 10 \frac{m}{s^{2}} \cdot 10 911 m = 112 383 300 \frac{N}{m^{2}} = 112383300 Pa \approx 112,4 MPa 1030 \frac{kg}{m^{3}} \cdot 10 \frac{m}{s^{2}} \cdot 10 911 m = 112 383 300 \frac{N}{m^{2}} = 112383300 Pa \approx 112,4 MPa](https://tex.z-dn.net/?f=1030+%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%7D+%5Ccdot+10+%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D+%5Ccdot+10+911+m+%3D+112+383+300+%5Cfrac%7BN%7D%7Bm%5E%7B2%7D%7D+%3D++112383300+Pa+%5Capprox+112%2C4+MPa)