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x= -2 ∨ x=5 ∨ 2x=3/:2
x=3/2
x= -2
x=3/2=1,5
x=5
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x(x+3)²(2x+3)³=0 ⇔ x=0 ∨(x+3)²=0 ∨ (2x+3)³=0
(x+3)²=0 ⇔ x+3=0
x= -3
(2x+3)³=0 ⇔ 2x+3=0
2x= -3/:2
x= -3/2
x= -3
x= -3/2
x=0
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x²(x-7)(x²-49)=0 ⇔ x²=0 ∨ x-7=0 ∨ x²-49=0
x=0 ∨ x=7 ∨ x²=49 ⇔ x=7 ∨ x= -7
x=0
x= -7
x=7
---------------------------------
x³=8
x³= -8
x=∛-8
x= -2
------------------------------
x³-9=0
x³=9
x=∛9
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x^4-8x^2=0
x²(x²-8)=0 wylaczono wspoly czynnik x² przed nawias
x²(x²-8)=0 ⇔ x²=0 ∨ x²-8=0
x=0
x²-8=0
x²=8
x=√8 ∨ x= -√8
x= -√8
x=0
x=√8
-----------------------------------
x^5=9x^3
x^5-9x^3=0
x^3(x^2-9)=0 ⇔ x^3=0 ∨x^2-9=0
x^3=0 ⇔ x=0
x^2-9=0
x^2=9 ⇔ x=3 ∨ x= -3
x= -3
x=0
x=3
----------------------------------
(x^2-9)(2x+1)=0 ⇔ x^2-9=0 ∨2x+1=0
x^2-9=0
x^2=9 ⇔ x=3 ∨ x= -3
2x+1=0
2x= -1/:2
x= -1/2
x= -3
x= -1/2
x=3
------------------------------
x^4=x^2(x-1)
x^4 - x^2(x-1)=0 wylaczamy x^2 przed nawias
x^2 [ x^2 - (x-1) ]=0 ⇔ x^2=0 ∨ x^2 - (x-1)=0
x^2=0 ⇔ x=0
x^2-(x-1)=0
x^2-x+1=0
Δ=b^2-4ac
Δ=1-4*1*1
Δ=1-4
Δ= -3
Δ < 0 a zatem to rownanie nie ma rzwiazania
Rozwiazaniem danego rownania jest x=0