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x-7-5x=r
3x+3=-4x-7
3x+4x=-7-3
7x=-10
x=-10/7
a(k)=(a(k-1)+a(k+1))/2
Mamy zatem
5x=((2x-3)+(x-7))/2
10x=2x-3+x-7
10x=3x-10
7x=-10
x=-10/7