f○f(f(1)) = f○f(1² + 2) x nya 1 jadi pakai yang x² + 2
= f○f(3)
= f(f(3)) x nya 3 jadi pakai yang 3(x+1)
= f(3(3+1))
= f(3(4))
= f(12) x nya 12 jadi pakai yang 2x+1
= 2.12 + 1
= 25
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f○f(f(1)) = f○f(1² + 2) x nya 1 jadi pakai yang x² + 2
= f○f(3)
= f(f(3)) x nya 3 jadi pakai yang 3(x+1)
= f(3(3+1))
= f(3(4))
= f(12) x nya 12 jadi pakai yang 2x+1
= 2.12 + 1
= 25