Jawaban:
konsentrasi urea adalah 1,78 M
Penjelasan:
Kenaikan titik didih
Tb larutan = 100,93°C (berdasarkan gambar grafik)
ΔTb = Tb larutan - Tb pelarut
ΔTb = 100,93 - 100
ΔTb = 0,93°C
ΔTb = m x Kb
0,93 = m x 0,52
m urea =
m urea = 1,7884615384615384615384615384615
m urea = 1,78 molal
artinya 1,78 mol urea dilarutkan dalam 1000 gram pelarut.
M urea = n x
M urea = 1,78 x
M urea = 1,78 M
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Verified answer
Jawaban:
konsentrasi urea adalah 1,78 M
Penjelasan:
Kenaikan titik didih
Tb larutan = 100,93°C (berdasarkan gambar grafik)
ΔTb = Tb larutan - Tb pelarut
ΔTb = 100,93 - 100
ΔTb = 0,93°C
ΔTb = m x Kb
0,93 = m x 0,52
m urea =
m urea = 1,7884615384615384615384615384615
m urea = 1,78 molal
artinya 1,78 mol urea dilarutkan dalam 1000 gram pelarut.
M urea = n x
M urea = 1,78 x
M urea = 1,78 M
Pelajari lebih lanjut