Question

Hola me ayudas con esta tarea por fis

Answer 1

Ok Area del triangulo mayor = 1 Cm²

Triangulos Intermedios 4 ==>  1 Cm² / 4 = (1/4)Cm²

Area de un triangulo intermedio = (1/4) Cm²

Area de los 4 Triangulos Intermedios = (1/4)x4 = 1 Cm²

Triangulos Pequeños 4 ===> (1/4)/4 =

Area de un triangulo Pequeño = 1/16 Cm²

Area 4 triangulos Pequeños = (1/16)x4 = (1/4) Cm²

Area Total = 1 Cm² + 1 Cm² + (1/4) Cm²

Area Total = (4/4) Cm² + (4/4) Cm² + (1/4) Cm² = (9/4) Cm²

Area Total = (9/4) Cm²