January 2019 1 41 Report
Granica funkcji w punkcie.

Oblicz granice:
a) lim_x_\rightarrow_1 \frac{ \sqrt[3]{2x-1} -1}{x-1}
b) lim_x_\rightarrow_3 \ \frac{ \sqrt[3]{1-3x} +2}{x-3}

Wyznacz parametr a, wiedząc, że:
 \lim_{x \to ^-\infty} \frac{\sqrt[]{ax^2+2} }{3x+a}=-2

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