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y: lado corto
z: tercer lado
plantear ecuaciones
x = y+2
z = 2y-5
x+y+z = 21
resolver sistema de ecuaciones 3×3
método de sustitución
y+2+y+2y-5 = 21
4y-3 = 21
4y = 24
y = 6
z = 2y-5
z = 2(6)-5
z = 12-5
z = 7
x = y+2
x = 6+2
x = 8
por tanto
el lado largo mide 8 cm
el lado corto mide 6 cm
el tercer lado mide 7 cm