Dwa zadania w załączniku.
Dam naj :)
zad.1
Obliczenia do reakcji w załączniku.
M(KOH)=39g+16g+1g=56g
1mol kwasu -------------- 3*56g KOH
3*56g=168g
ms=168g
Cp=20%
mr=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:Cp
mr=ms*100%/Cp
mr=168g*100%/20%
mr=840g
zad.2
Odp: C
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zad.1
Obliczenia do reakcji w załączniku.
M(KOH)=39g+16g+1g=56g
1mol kwasu -------------- 3*56g KOH
3*56g=168g
ms=168g
Cp=20%
mr=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:Cp
mr=ms*100%/Cp
mr=168g*100%/20%
mr=840g
zad.2
Odp: C